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求值:log以3为底根号27的对数+lg25+lg4+7的log7为...

你参考看看~

你把题看错了 应该是4次根号下27 可以化成3的3/4次方 原式=log 3^(-1/4)+lg(2.5*4)+2 3 =-1/4+lg10+2 =-1/4+1+2 =11/4

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log3 根号27+lg25+lg4+7的log2幂+(-9.8)º = 3/2 + lg100 + 7^0.3010 +1 = 3/2 + 2 + 1.8 +1 = 6.3

原式=log3332+lg(25×4)+2-[(23)3]?13=32+2+2?32=4.故答案为:4.

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(log5√2×log4981) ÷(log251/3×log74∧3) =[1/2 lg2×4 lg3/( lg5×2 lg7)]/[- lg3×6 lg2/(2 lg5×lg7)] =( lg2× lg3/ lg5× lg7)/(-3 lg2× lg3/ lg5×lg7) =-1/3

如果数是分母4倍根号27,分子3则=log 3 3^(3/4)-log 3 3=3/4-1=-1/4 如果数是4/3倍根号,根号内27,则=log 3 27^(3/4)=log 3 3^(9/4)=9/4

[log(5)(根号2)*log(7)9]/[log(5)(1/3)*log(5)(4的立方根)] ={[lg(根号2)/lg5]*(lg9/lg7)}/{[lg(1/3)/lg5]*[lg4的立方根/lg5] 换底公式 =[(1/2)lg2*(2lg3)/(lg5*lg7)]/[(-lg3*lg5)/(2/3)*lg2*lg5] =(-3/2)*(lg2*lg3*lg5*lg5)/(lg5*lg7*lg3*lg2) ...

log2(3)=a, log3(7)=b log12(56)=log2(7*2³)/log2(3*2²)=[log2(7)+log2(3)]/[log2(3)+2)] =[log3(7)/log3(2)+3]/[a+2] =[ab+3]/[a+2]

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